When we calculate the pressure drop ΔP = \(\frac{XFL}{D} \frac{v^2}{2g}\)×ϸ, what is the value X?

When we calculate the pressure drop ΔP = \(\frac{XFL}{D} \frac{v^2}

1.	When we calculate the pressure drop ΔP = \(\frac{XFL}{D} \frac{v^2}{2g}\)×ϸ, what is the value X?
A.	2
B.	4
C.	5
D.	8
Answer» C. 5

Discussion

No Comment Found

Related MCQs

Consider we have a Double Pipe Heat Exchanger, with the inner tube of diameter 20mm (neglect thickness) and outer tube of diameter 30mm. We have two fluids A & B (both with viscosity 2.5×10-5Pa-s), we desire to have their flow rates as 15 Kg/s and 21 Kg/s respectively. What is the Friction Factor (F) for this setup for the annulus pipe?
In the calculation of Reynold’s Number for the Friction factor of the annulus tube, which is the correct formula for equivalent diameter De?
Consider we have a Double Pipe Heat Exchanger, with the inner tube of Outer diameter 20mm (thickness 2mm) and outer tube of inner diameter 30mm. We have two fluids A & B, both of density 990 Kg/m3, we desire to have their flow rates as 15m/s and 21m/s respectively, friction factor of 0.0096 and 5 hairpins of length 0.4 metre. If the maximum pressure drop allowed is 10psi, is the setup suitable for industrial use?
What is the Pressure drop equivalent for 7 Hairpins?
Consider we have a Double Pipe Heat Exchanger, with the inner tube of Outer diameter 20mm (thickness 2mm) and outer tube of inner diameter 30mm. We have two fluids A & B, both of density 990 Kg/m3, we desire to have their flow rates as 15m/s and 21m/s respectively, friction factor of 0.00096 and 5 hairpins of length 0.4 metre. What is the value of Pressure drop for the inner tube?
When we calculate the pressure drop ΔP = \(\frac{XFL}{D} \frac{v^2}{2g}\)×ϸ, what is the value X?
For calculating the pressure drop in a double pipe heat exchanger,(i) We calculate Reynolds number(ii) We calculate the length of the tube required(iii) We calculate heat transfer coefficient for both sides(iv) We calculate the Friction factor for both sides
Consider we have a Double Pipe Heat Exchanger, with the inner tube of Outer diameter 20mm(thickness 2mm) and outer tube of inner diameter 30mm. We have two fluids A & B, both of density 990 Kg/m3, we desire to have their flow rates as 15m/s and 21 m/s respectively, friction factor of 0.00096 and length of the tube as 1metre. What is the value of Pressure drop for the inner tube?
In the calculation of Friction Factor on the annulus/tube side for heat transferred, which is the correct formula for Friction Factor?
Consider we have a Double Pipe Heat Exchanger, with the inner tube of Outer diameter 20mm (thickness 2mm) and outer tube of inner diameter 30mm. We have two fluids A & B, we desire to have their flow rates as 15 m/s and 21 m/s respectively, friction factor of 0.0096 and length of the tube as 1metre. What is the value of hfs for the inner tube?

When we calculate the pressure drop ΔP = \(\frac{XFL}{D} \frac{v^2}{2g}\)×ϸ, what is the value X?

Discussion

No Comment Found

Related MCQs

Reply to Comment