

MCQOPTIONS
Saved Bookmarks
1. |
In the calculation of Friction Factor on the annulus/tube side for heat transferred, which is the correct formula for Friction Factor? |
A. | F = 0.0035+ \(\frac{0.264}{Re^{0.42}}\) |
B. | F = 0.0027+ \(\frac{0.264}{Re^{0.42}}\) |
C. | F = 0.0035+ \(\frac{0.42}{Re^{0.264}}\) |
D. | F = 0.0027+ \(\frac{0.42}{Re^{0.264}}\) |
Answer» B. F = 0.0027+ \(\frac{0.264}{Re^{0.42}}\) | |