What will be the output of the following C code?#include void main() { int var[4] = {11, 21, 31, 41}; int *ptr1 = var; int **ptr2 = &ptr1; printf("%p %p", *ptr2, var); }

Question

What will be the output of the following C code?#include <stdio.h> void main() { int var[4] = {11, 21, 31, 41}; int *ptr1 = var; int **ptr2 = &ptr1; printf("%p %p", *ptr2, var); }

TuteeHUB · Accepted Answer

Different memory address is printed.

TuteeHUB · Answer

Same memory address is printed.

TuteeHUB · Answer

11, 21, 31, 41

TuteeHUB · Answer

41, 31

TuteeHUB · Answer

None of these

1.	What will be the output of the following C code?#include <stdio.h> void main() { int var[4] = {11, 21, 31, 41}; int ptr1 = var; int ptr2 = &ptr1; printf("%p %p", ptr2, var); }
A.	Same memory address is printed.
B.	Different memory address is printed.
C.	11, 21, 31, 41
D.	41, 31
E.	None of these
Answer» B. Different memory address is printed.

What will be the output of the following C code?#include <stdio.h> void main() { int var[4] = {11, 21, 31, 41}; int *ptr1 = var; int **ptr2 = &ptr1; printf("%p %p", *ptr2, var); }

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What will be the output of the following C code?#include &lt;stdio.h&gt; void main() { int var[4] = {11, 21, 31, 41}; int *ptr1 = var; int **ptr2 = &amp;ptr1; printf("%p %p", *ptr2, var); }

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What will be the output of the following C code?#include <stdio.h> void main() { int var[4] = {11, 21, 31, 41}; int *ptr1 = var; int **ptr2 = &ptr1; printf("%p %p", *ptr2, var); }