1.

What will be the equation of normal to the hyperbola 3x2 4y2 = 12 at the point (x1, y1)?

A. 3x<sub>1</sub>y + 4y<sub>1</sub>x + 7x<sub>1</sub>y<sub>1</sub> = 0
B. 3x<sub>1</sub>y + 4y<sub>1</sub>x 7x<sub>1</sub>y<sub>1</sub> = 0
C. 3x<sub>1</sub>y 4y<sub>1</sub>x 7x<sub>1</sub>y<sub>1</sub> = 0
D. 3x<sub>1</sub>y 4y<sub>1</sub>x + 7x<sub>1</sub>y<sub>1</sub> = 0
Answer» C. 3x<sub>1</sub>y 4y<sub>1</sub>x 7x<sub>1</sub>y<sub>1</sub> = 0


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