What will be the equation of normal to the hyperbola 3x2 – 4y2 = 12 – McqOptions

MCQOPTIONS

1.	What will be the equation of normal to the hyperbola 3x2 – 4y2 = 12 at the point (x1, y1)?
A.	3x1y + 4y1x + 7x1y1 = 0
B.	3x1y + 4y1x – 7x1y1 = 0
C.	3x1y – 4y1x – 7x1y1 = 0
D.	3x1y – 4y1x + 7x1y1 = 0
Answer» C. 3x1y – 4y1x – 7x1y1 = 0

Discussion

No Comment Found

Related MCQs

What is the foot of the normal if the straight line x + y + 7 = 0 is normal to the hyperbola 3x2 – 4y2 = 12 whose normal is at the point (x1, y1)?
What is the nature of the straight line x + y + 7 = 0 to the hyperbola 3x2 – 4y2 = 12 whose normal is at the point (x1, y1)?
What will be the equation of normal to the hyperbola 3x2 – 4y2 = 12 at the point (x1, y1)?
What is the equation of the tangent to the parabola y2 = 8x, which is inclined at an angle of 45° with the x axis?
What will be the equation of the tangent to the circle x2 + y2 – 6x + 4y – 7 = 0, which are perpendicular to the straight line 2x – y + 3 = 0?
At which point does the normal to the hyperbola xy = 4 at (2, 2) intersects the hyperbola again?
What will be the equation of the normal to the hyperbola xy = 4 at the point (2, 2)?
If X and Y are given as current co-ordinates, what is the equation of the tangent at a specific point of x3 – 3axy + y3 = 0 at (x, y)?
What is the equation of the tangent at a specific point of y2 = 4ax at (0, 0)?