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| 1. |
What is the power at the load of a series equalizer? |
| A. | [ V<sub>max</sub><sup>2</sup>/(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup> )]R<sub>o</sub> |
| B. | [ V<sub>max</sub><sup>2</sup>/(2(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
| C. | [ V<sub>max</sub><sup>2</sup>/(3(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
| D. | [ V<sub>max</sub><sup>2</sup>/(4(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
| Answer» E. | |