 
			 
			MCQOPTIONS
 Saved Bookmarks
				| 1. | What is the load current in terms of Vmax in the shunt equalizer? | 
| A. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) | 
| B. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) | 
| C. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) | 
| D. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) | 
| Answer» D. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) | |