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1. |
What is the formula for Lagrange’s theorem?a) f’(c) = \(\frac {f(a)+f(b)}{b-a}\) b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\) c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\) d) f’(c) = \(\frac {f( |
A. | f’(c) = \(\frac {f(a)+f(b)}{b-a}\) b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\) c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\) d) f’(c) = \(\frac {f(a)-f( |
B. | }{b-a}\) b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\) c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\) d) f’( |
C. | = \(\frac {f(a)+f(b)}{b-a}\) b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\) c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\) |
D. | f’(c) = \(\frac {f(a)-f(b)}{b+a}\) |
Answer» C. = \(\frac {f(a)+f(b)}{b-a}\) b) f’(c) = \(\frac {f(b)-f(a)}{b-a}\) c) f’(c) = \(\frac {f(a)+f(b)}{b+a}\) | |