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1. |
What is the expression for the traction term tn in the element load vector Qe=∮┌cheψTtds of the following figure where L23 is the length of the line 2-3? |
A. | tn=-T(-1+\(\frac{s}{L_{23}})\) |
B. | tn=T(-1+\(\frac{s}{L_{23}})\) |
C. | tn=-T(1+\(\frac{s}{L_{23}})\) |
D. | tn=T(1+\(\frac{s}{L_{23}})\) |
Answer» C. tn=-T(1+\(\frac{s}{L_{23}})\) | |