1.

What is the equivalent capacitance when the 2 capacitors are connected in series?

A. Cs = C1 + C2
B. Cs = \(\frac {1}{C_1} + \frac {1}{C_2}\)
C. Cs = C1 + \(\frac {1}{C_2}\)
D. Cs = \(\frac {1}{C_1}\) + C2
Answer» C. Cs = C1 + \(\frac {1}{C_2}\)


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