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1. |
What is the equivalent capacitance when the 2 capacitors are connected in series? |
A. | Cs = C1 + C2 |
B. | Cs = \(\frac {1}{C_1} + \frac {1}{C_2}\) |
C. | Cs = C1 + \(\frac {1}{C_2}\) |
D. | Cs = \(\frac {1}{C_1}\) + C2 |
Answer» C. Cs = C1 + \(\frac {1}{C_2}\) | |