1.

What is the equivalent capacitance when the 2 capacitors are connected in series?

A. C<sub>s</sub> = C<sub>1</sub> + C<sub>2</sub>
B. C<sub>s</sub> = ( frac {1}{C_1} + frac {1}{C_2} )
C. C<sub>s</sub> = C<sub>1</sub> + ( frac {1}{C_2} )
D. C<sub>s</sub> = ( frac {1}{C_1} ) + C<sub>2</sub>
Answer» C. C<sub>s</sub> = C<sub>1</sub> + ( frac {1}{C_2} )


Discussion

No Comment Found