What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\fra

1.	What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
A.	x=±5
B.	y=±5
C.	x=±2
D.	y=±2
Answer» B.

Discussion

If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is conjugate axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is transverse axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}{9})^2\)=1.
Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1.