Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}

1.	Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}{9})^2\)=1.
A.	(±5,0)
B.	(±4,0)
C.	(0,±5)
D.	(0,±4)
Answer» D.

Discussion

If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is conjugate axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is transverse axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}{9})^2\)=1.
Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1.