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1. |
What do we get after factorising x3+ 8y3+ z3 4xyz? |
A. | (x + 2y + z) (x<sup>2</sup> + 4y<sup>2</sup> + z<sup>2</sup> 2xy 2yz zx) |
B. | (x + 2y + z) (x<sup>2</sup> + 4y<sup>2</sup> + z<sup>2</sup> 2xy 2yz zx) |
C. | (x + 2y + z) (x<sup>2</sup> + 4y<sup>2</sup> + z<sup>2</sup> 2xy 2yz zx) |
D. | (x + 2y + z) (x<sup>2</sup> + 4y<sup>2</sup>+ z<sup>2</sup> 2xy 2yz zx) |
Answer» D. (x + 2y + z) (x<sup>2</sup> + 4y<sup>2</sup>+ z<sup>2</sup> 2xy 2yz zx) | |