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				| 1. | We wish to see inside an atom. Assuming the atom to have a diameter of 100 pm, this means that one must be able to resolved a width of say 10 p.m. If an electron microscope is used, the minimum electron energy required is about [AIIMS 2004] | 
| A. | 1.5 KeV | 
| B. | 15 KeV | 
| C. | \[\frac{bc}{a}\] | 
| D. | 1.5 KeV | 
| Answer» C. \[\frac{bc}{a}\] | |