We know ID =1/2 kn (VGS + vgs – Vt)2. Let the signal vgs be a sine wave with amplitude Vgs, and substitute vgs = Vgs sin ω t in Eq.(5.43). Using the trigonometric identity show that the ratio of the signal at frequency 2ω to that at frequency ω , expressed as a percentage (known as the second-harmonic distortion) is

We know ID =1/2 kn (VGS + vgs – Vt)2. Let the signal vgs be a sine w

1.	We know ID =1/2 kn (VGS + vgs – Vt)2. Let the signal vgs be a sine wave with amplitude Vgs, and substitute vgs = Vgs sin ω t in Eq.(5.43). Using the trigonometric identity show that the ratio of the signal at frequency 2ω to that at frequency ω , expressed as a percentage (known as the second-harmonic distortion) is
A.	Vgs/Vov x 100%
B.	1/2Vgs/Vov x 100%
C.	1/4Vgs/Vov x 100%
D.	1/8Vgs/Vov x 100%
Answer» D.

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