1.

Two circle C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If BDC = 120o, then the value of ABP is equal to -

A. $$120^o$$
B. $$40^o$$
C. $$110^o$$
D. $$60^o$$
Answer» E.


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