The z-transform of x[n]= {2,4,5,7,0,1} (5 as the reference variable)

1.	The z-transform of x[n]= {2,4,5,7,0,1} (5 as the reference variable) is ___________
A.	2z2 + 4z + 5 +7z + z3, z≠∞
B.	2z-2 + 4z-1 + 5 + 7z + z3, z≠∞
C.	2z-2 + 4z-1 + 5 + 7z + z3, 0<\|z\|<∞
D.	2z2 + 4z + 5 + 7z-1 + z3, 0<\|z\|<∞
E.	is ___________a) 2z2 + 4z + 5 +7z + z3, z≠∞b) 2z-2 + 4z-1 + 5 + 7z + z3, z≠∞c) 2z-2 + 4z-1 + 5 + 7z + z3, 0<\|z\|<∞d) 2z2 + 4z + 5 + 7z-1 + z3, 0<\|z\|<∞
Answer» E. is ___________a) 2z2 + 4z + 5 +7z + z3, z≠∞b) 2z-2 + 4z-1 + 5 + 7z + z3, z≠∞c) 2z-2 + 4z-1 + 5 + 7z + z3, 0<\|z\|<∞d) 2z2 + 4z + 5 + 7z-1 + z3, 0<\|z\|<∞

Discussion

Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x[n]*x [n-3] is __________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x [-n]*x[n] is ____________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal y[n] = \(\frac{1}{2^n}\) x[n] is _________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x [n-2] is _________
The z-transform of x[n]= {1,0,-1,0,1,-1} (1st 1 as the reference variable) is __________
The z-transform of x[n]= {2,4,5,7,0,1} (5 as the reference variable) is ___________
The z-transform of {3,0,0,0,0,6,1,-4} (1 as the reference variable) is ___________
The z-transform of \((\frac{2}{3})^{[n]}\) is ____________
The z-transform of \((\frac{1}{4})^4\) u[-n] is ___________
The z-transform of \((\frac{1}{4})^n\) (u[n] – u[n-5]) is __________