Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\),

1.	Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), \|z\|<4The z-transform of the signal x [-n]*x[n] is ____________
A.	\(\frac{z^2}{16z^2-257z^4-16}\)
B.	\(\frac{-16z^2}{(z^2-16)^2}\)
C.	\(\frac{z^2}{(257z^2-16z^4-16)}\)
D.	\(\frac{16z^2}{(z^2-16)^2}\)
Answer» D. \(\frac{16z^2}{(z^2-16)^2}\)

Discussion

Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x[n]*x [n-3] is __________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x [-n]*x[n] is ____________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal y[n] = \(\frac{1}{2^n}\) x[n] is _________
Given the z-transform pair\(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4The z-transform of the signal x [n-2] is _________
The z-transform of x[n]= {1,0,-1,0,1,-1} (1st 1 as the reference variable) is __________
The z-transform of x[n]= {2,4,5,7,0,1} (5 as the reference variable) is ___________
The z-transform of {3,0,0,0,0,6,1,-4} (1 as the reference variable) is ___________
The z-transform of \((\frac{2}{3})^{[n]}\) is ____________
The z-transform of \((\frac{1}{4})^4\) u[-n] is ___________
The z-transform of \((\frac{1}{4})^n\) (u[n] – u[n-5]) is __________