The value of ‚Äö√Ñ√∂‚àö√ë‚àö‚â§c‚Äö√Ñ√∂‚àö√ë‚àö¬• in complementary function of ‚Äö√Ñ√∂‚àö√ë‚àö‚â§i‚Äö√Ñ√∂‚àö√ë‚àö¬• is?$

Question

TuteeHUB · Accepted Answer

c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R²+(‚âà√¨‚àö¬¢L)²) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan^-1(‚âà√¨‚àö¬¢L/R))

TuteeHUB · Answer

c = -V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R2+(‚âà√¨‚àö¬¢L)2) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan-1(‚âà√¨‚àö¬¢L/R))

TuteeHUB · Answer

c = -V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R2+(‚âà√¨‚àö¬¢L)2) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®-tan-1(‚âà√¨‚àö¬¢L/R))

TuteeHUB · Answer

c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R2+(‚âà√¨‚àö¬¢L)2) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan-1(‚âà√¨‚àö¬¢L/R))

TuteeHUB · Answer

c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R2+(‚âà√¨‚àö¬¢L)2) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®-tan-1(‚âà√¨‚àö¬¢L/R))

1.	The value of ‚Äö√Ñ√∂‚àö√ë‚àö‚â§c‚Äö√Ñ√∂‚àö√ë‚àö¬• in complementary function of ‚Äö√Ñ√∂‚àö√ë‚àö‚â§i‚Äö√Ñ√∂‚àö√ë‚àö¬• is?$
A.	c = -V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R<sup>2</sup>+(‚âà√¨‚àö¬¢L)<sup>2</sup>) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan<sup>-1</sup>(‚âà√¨‚àö¬¢L/R))
B.	c = -V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R<sup>2</sup>+(‚âà√¨‚àö¬¢L)<sup>2</sup>) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®-tan<sup>-1</sup>(‚âà√¨‚àö¬¢L/R))
C.	c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R<sup>2</sup>+(‚âà√¨‚àö¬¢L)<sup>2</sup>) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan<sup>-1</sup>(‚âà√¨‚àö¬¢L/R))
D.	c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R<sup>2</sup>+(‚âà√¨‚àö¬¢L)<sup>2</sup>) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®-tan<sup>-1</sup>(‚âà√¨‚àö¬¢L/R))
Answer» C. c = V/‚Äö√Ñ√∂‚àö‚Ä†‚àö‚àÇ(R<sup>2</sup>+(‚âà√¨‚àö¬¢L)<sup>2</sup>) cos‚Äö√Ñ√∂‚àö√ñ¬¨‚àû(‚âà√≠‚Äö√†√®+tan<sup>-1</sup>(‚âà√¨‚àö¬¢L/R))

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