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1. |
In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The particular integral of the solution of ‘ip’ is? |
A. | ip = 0.98cos(1000t+π/2-78.6o) |
B. | ip = 0.98cos(1000t-π/2-78.6o) |
C. | ip = 0.98cos(1000t-π/2+78.6o) |
D. | ip = 0.98cos(1000t+π/2+78.6o) |
Answer» B. ip = 0.98cos(1000t-π/2-78.6o) | |