MCQOPTIONS
Saved Bookmarks
| 1. |
The unit of permittivity of free space, \[{{\varepsilon }_{0}}\]is |
| A. | \[coulom{{b}^{2}}/{{(newton-metre)}^{2}}\] |
| B. | coulomb/newton-metre |
| C. | \[newton-mete{{r}^{2}}/coulom{{b}^{2}}\] |
| D. | \[coulom{{b}^{2}}/newton-metr{{e}^{2}}\] |
| Answer» E. | |