Let$$[{{\in }_{0}}]$$denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:

Question

TuteeHUB · Accepted Answer

$${{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}{{A}^{2}}]$$

TuteeHUB · Answer

$${{\in }_{0}}=[{{M}^{-1}}{{L}^{-3}}{{T}^{2}}A]$$

TuteeHUB · Answer

$${{\in }_{0}}=[{{M}^{1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}]$$

TuteeHUB · Answer

$${{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}A]$$

1.	Let\[[{{\in }_{0}}]\]denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then:
A.	\[{{\in }_{0}}=[{{M}^{-1}}{{L}^{-3}}{{T}^{2}}A]\]
B.	\[{{\in }_{0}}=[{{M}^{1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}]\]
C.	\[{{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}{{A}^{2}}]\]
D.	\[{{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}A]\]
Answer» C. \[{{\in }_{0}}=[{{M}^{1}}{{L}^{2}}{{T}^{1}}{{A}^{2}}]\]

Let\[[{{\in }_{0}}]\]denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then: