The time taken by all-to- all broadcast on a mesh is. – McqOptions

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1.	The time taken by all-to- all broadcast on a mesh is.
A.	t= (ts + twm)(p-1)
B.	t= ts logp + twm(p-1)
C.	t= 2ts(√p – 1) - twm(p-1)
D.	t= 2ts(√p – 1) + twm(p-1)
Answer» B. t= ts logp + twm(p-1)

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