The plaintext message consist of single letters with 5-bit numerical equivalents from (00000)2 to (11001)2. The secret deciphering key is the superincreasing 5-tuple (2, 3, 7, 15, 31), m = 61 and a = 17. Find the ciphertext for the message “WHY”.$#

• A. C= (148, 143, 50)
• B. C= (148, 143, 56)
• C. C= (143, 148, 92)
• D. C= (148, 132,92)