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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Cryptography and Network Security knowledge and support exam preparation. Choose a topic below to get started.
1. |
“In ECC, the inverse of point P =(x1, y1) is Q = (-x1, y1). “ |
A. | True |
B. | False |
Answer» C. | |
2. |
“Elliptic curve cryptography follows the associative property.” |
A. | True |
B. | False |
Answer» B. False | |
3. |
How many real and imaginary roots does the equation y2=x3-4x have |
A. | 2 real, 1 imaginary |
B. | all real |
C. | all imaginary |
D. | 2 imaginary, 1 real |
Answer» C. all imaginary | |
4. |
‚Äö√Ñ√∂‚àö√ë‚àö‚à´In ECC, the inverse of point P =(x1, y1) is Q = (-x1, y1). ‚Äö√Ñ√∂‚àö√ë‚àö‚à?# |
A. | True |
B. | False |
Answer» C. | |
5. |
“Elliptic curve cryptography follows the associative property.”$ |
A. | True |
B. | False |
Answer» B. False | |
6. |
In the elliptic curve group defined by y2= x3- 17x + 16 over real numbers, what is 2P if P = (4, 3.464)? |
A. | (12.022, -39.362) |
B. | (32.022, 42.249) |
C. | (11.694, -43.723) |
D. | (43.022, 39.362) |
Answer» B. (32.022, 42.249) | |
7. |
In the elliptic curve group defined by y2= x3- 17x + 16 over real numbers, what is P + Q if P = (0,-4) and Q = (1, 0)? |
A. | (15, -56) |
B. | (-23, -43) |
C. | (69, 26) |
D. | (12, -86) |
Answer» B. (-23, -43) | |
8. |
How many real and imaginary roots does the equation y2=x3-1 have |
A. | 2 real, 1 imaginary |
B. | all real |
C. | all imaginary |
D. | 2 imaginary, 1 real |
Answer» E. | |
9. |
In Singular elliptic curve, the equation x^3+ax+b=0 does ____ roots. |
A. | does not have three distinct |
B. | has three distinct |
C. | has three unique |
D. | has three distinct unique |
Answer» B. has three distinct | |
10. |
What is the general equation for elliptic curve systems? |
A. | y<sup>3</sup>+b_1 xy+b_2 y=x<sup>3</sup>3+a_1 x<sup>2</sup>+a_2 x+a_3 |
B. | y<sup>3</sup>+b_1 x+b_2 y=x<sup>2</sup>+a_1 x<sup>2</sup>+a_2 x+a_3 |
C. | y<sup>2</sup>+b_1 xy+b_2 y=x<sup>3</sup>+a_1 x<sup>2</sup>+a_2 |
D. | y<sup>2</sup>+b_1 xy+b_2 y=x<sup>3</sup>+a_1 x<sup>2</sup>+a_2 x+a_3 |
Answer» E. | |