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1. |
The plaintext message consist of single letters with 5-bit numerical equivalents from (00000)2 to (11001)2. The secret deciphering key is the superincreasing 5-tuple (2, 3, 7, 15, 31), m = 61 and a = 17. Find the ciphertext for the message “WHY”. |
A. | C= (148, 143, 50) |
B. | C= (148, 143, 56) |
C. | C= (143, 148, 92) |
D. | C= (148, 132,92) |
Answer» B. C= (148, 143, 56) | |