The output current equation for MC1408 digital to analog converter would be

Question

TuteeHUB · Accepted Answer

I_o= -(V_ref/2R₁)‚Äö√†√∂‚àö‚â•[(D₇/2)+(D₆/4)+(D₅/8)+(D₄/16)+(D₃/32)+(D₂/64)+(D₁/128)+(D₀/256)].

TuteeHUB · Answer

Io= -(Vref/R1)‚Äö√†√∂‚àö‚â•[(D7/2)+(D6/4)+(D5/8)+(D4/16)+(D3/32)+(D2/64)+(D1/128)+(D0/256)].

TuteeHUB · Answer

Io= (Vref/2R1)‚Äö√†√∂‚àö‚â•[(D7/2)+(D6/4)+(D5/8)+(D4/16)+(D3/32)+(D2/64)+(D1/128)+(D0/256)].

TuteeHUB · Answer

Io= (Vref/R1)‚Äö√†√∂‚àö‚â•[(D7/2)+(D6/4)+(D5/8)+(D4/16)+(D3/32)+(D2/64)+(D1/128)+(D0/256)].

TuteeHUB · Answer

Io= -(Vref/2R1)‚Äö√†√∂‚àö‚â•[(D7/2)+(D6/4)+(D5/8)+(D4/16)+(D3/32)+(D2/64)+(D1/128)+(D0/256)].

1.	The output current equation for MC1408 digital to analog converter would be
A.	I<sub>o</sub>= -(V<sub>ref</sub>/R<sub>1</sub>)‚Äö√†√∂‚àö‚â•[(D<sub>7</sub>/2)+(D<sub>6</sub>/4)+(D<sub>5</sub>/8)+(D<sub>4</sub>/16)+(D<sub>3</sub>/32)+(D<sub>2</sub>/64)+(D<sub>1</sub>/128)+(D<sub>0</sub>/256)].
B.	I<sub>o</sub>= (V<sub>ref</sub>/2R<sub>1</sub>)‚Äö√†√∂‚àö‚â•[(D<sub>7</sub>/2)+(D<sub>6</sub>/4)+(D<sub>5</sub>/8)+(D<sub>4</sub>/16)+(D<sub>3</sub>/32)+(D<sub>2</sub>/64)+(D<sub>1</sub>/128)+(D<sub>0</sub>/256)].
C.	I<sub>o</sub>= (V<sub>ref</sub>/R<sub>1</sub>)‚Äö√†√∂‚àö‚â•[(D<sub>7</sub>/2)+(D<sub>6</sub>/4)+(D<sub>5</sub>/8)+(D<sub>4</sub>/16)+(D<sub>3</sub>/32)+(D<sub>2</sub>/64)+(D<sub>1</sub>/128)+(D<sub>0</sub>/256)].
D.	I<sub>o</sub>= -(V<sub>ref</sub>/2R<sub>1</sub>)‚Äö√†√∂‚àö‚â•[(D<sub>7</sub>/2)+(D<sub>6</sub>/4)+(D<sub>5</sub>/8)+(D<sub>4</sub>/16)+(D<sub>3</sub>/32)+(D<sub>2</sub>/64)+(D<sub>1</sub>/128)+(D<sub>0</sub>/256)].
Answer» D. I<sub>o</sub>= -(V<sub>ref</sub>/2R<sub>1</sub>)‚Äö√†√∂‚àö‚â•[(D<sub>7</sub>/2)+(D<sub>6</sub>/4)+(D<sub>5</sub>/8)+(D<sub>4</sub>/16)+(D<sub>3</sub>/32)+(D<sub>2</sub>/64)+(D<sub>1</sub>/128)+(D<sub>0</sub>/256)].

Discussion