The inverse s-box permutation follows, b i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di

Question

TuteeHUB · Accepted Answer

di is the ith bit of a byte  d  whose hex value is 0x05

TuteeHUB · Answer

nHere di is

TuteeHUB · Answer

di is the ith bit of a byte  d  whose hex value is 0x15

TuteeHUB · Answer

di is the ith bit of a byte  d  whose hex value is 0x05

TuteeHUB · Answer

di is the ith bit of a byte  d  whose hex value is 0x25

TuteeHUB · Answer

di is the ith bit of a byte  d  whose hex value is 0x51

1.	The inverse s-box permutation follows, b i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di
A.	nHere di is
B.	di is the ith bit of a byte d whose hex value is 0x15
C.	di is the ith bit of a byte d whose hex value is 0x05
D.	di is the ith bit of a byte d whose hex value is 0x25
E.	di is the ith bit of a byte d whose hex value is 0x51
Answer» C. di is the ith bit of a byte d whose hex value is 0x05

Discussion