1.

In AES, to make the s-box, we apply the transformation b i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci

A. nWhat is ci in this transformation?
B. ci is the ith bit of byte c with value 0x63
C. ci is the ith bit of byte c with value 0x25
D. ci is the ith bit of byte c with value 0x8F
E. ci is the ith bit of byte c with value 0x8A
Answer» B. ci is the ith bit of byte c with value 0x63


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