The inverse of the matrix A=$\begin{bmatrix}1&2&4\5&2&4\3&6&2\end{bmatrix}$ is

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&0\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\ \frac{3}{40}&1&\frac{-1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&1\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&0\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{-1}{4}&-\frac{1}{4}&0\ \frac{1}{40}&\frac{1}{8}&\frac{-1}{5}\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}$

1.	The inverse of the matrix A=\(\begin{bmatrix}1&2&4\\5&2&4\\3&6&2\end{bmatrix}\) is
A.	\(\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&0\\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\\ \frac{3}{40}&1&\frac{-1}{10}\end{bmatrix}\)
B.	\(\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&1\\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}\)
C.	\(\begin{bmatrix}\frac{-1}{4}&\frac{1}{4}&0\\ \frac{1}{40}&\frac{-1}{8}&\frac{1}{5}\\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}\)
D.	\(\begin{bmatrix}\frac{-1}{4}&-\frac{1}{4}&0\\ \frac{1}{40}&\frac{1}{8}&\frac{-1}{5}\\ \frac{3}{40}&0&\frac{-1}{10}\end{bmatrix}\)
Answer» D.

The inverse of the matrix A=\(\begin{bmatrix}1&2&4\\5&2&4\\3&6&2\end{bmatrix}\) is