Find the inverse of A=$\begin{bmatrix}5&3\4&1\end{bmatrix}$.

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\begin{bmatrix}-\frac{1}{7}&\frac{3}{7}\\frac{4}{7}&-\frac{5}{7}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}-\frac{1}{7}&\frac{3}{7}\\frac{4}{7}&\frac{5}{7}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}-\frac{1}{7}&-\frac{3}{7}\\frac{4}{7}&-\frac{5}{7}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}0&\frac{3}{7}\\frac{4}{7}&\frac{5}{7}\end{bmatrix}$

1.	Find the inverse of A=\(\begin{bmatrix}5&3\\4&1\end{bmatrix}\).
A.	\(\begin{bmatrix}-\frac{1}{7}&\frac{3}{7}\\\frac{4}{7}&-\frac{5}{7}\end{bmatrix}\)
B.	\(\begin{bmatrix}-\frac{1}{7}&\frac{3}{7}\\\frac{4}{7}&\frac{5}{7}\end{bmatrix}\)
C.	\(\begin{bmatrix}-\frac{1}{7}&-\frac{3}{7}\\\frac{4}{7}&-\frac{5}{7}\end{bmatrix}\)
D.	\(\begin{bmatrix}0&\frac{3}{7}\\\frac{4}{7}&\frac{5}{7}\end{bmatrix}\)
Answer» B.

Find the inverse of A=\(\begin{bmatrix}5&3\\4&1\end{bmatrix}\).