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1. |
The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH + 0.036H2O and determine the product yield coefficient Y etoh/s and determine coefficient a. |
A. | 0.57 g. g⁻¹, 0.078 |
B. | 0.33 g. g⁻¹, 0.094 |
C. | 0.45 g. g⁻¹, 0.086 |
D. | 0.44 g. g⁻¹, 0.056 |
Answer» C. 0.45 g. g⁻¹, 0.086 | |