

MCQOPTIONS
Saved Bookmarks
1. |
The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2ODetermine the biomass (MW= 23.74) yield coefficient Y x/s |
A. | 0.078 g. g⁻¹ |
B. | 0.070 g. g⁻¹ |
C. | 0.068 g. g⁻¹ |
D. | 0.060 g. g⁻¹ |
Answer» B. 0.070 g. g⁻¹ | |