1.

The growth of S.cerevisiae on glucose under anaerobic conditions can be described by the following reaction:C6H12O6 + aNH3 → 0.59 CH1.64N0.16O0.52 (biomass) + 0.43 C3H8O3 + 1.54CO2 + 1.3C2H5OH +0.036H2ODetermine the biomass (MW= 23.74) yield coefficient Y x/s

A. 0.078 g. g⁻¹
B. 0.070 g. g⁻¹
C. 0.068 g. g⁻¹
D. 0.060 g. g⁻¹
Answer» B. 0.070 g. g⁻¹


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