1.

The CT for an abrupt PN junction diode is ________

A. CT = K/(V0+VB)1/2
B. CT = K/(V0+VB)-1/2
C. CT = K/(V0+VB)1/3
D. CT = K/(V0+VB)-1/3
Answer» B. CT = K/(V0+VB)-1/2


Discussion

No Comment Found