The correct relation between the emitter current Ie and the base current Ib is given by

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

Ib = (1 + ‚âà√≠¬¨¬±) Ie

TuteeHUB · Answer

Ib = (‚âà√≠¬¨¬± ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1) Ie

TuteeHUB · Answer

Ie = (1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚Äö√†√∂‚àö¬∫) Ib

TuteeHUB · Answer

Ie = (1 + ‚Äö√†√∂‚àö¬∫) Ib

1.	The correct relation between the emitter current Ie and the base current Ib is given by
A.	Ib = (1 + ‚âà√≠¬¨¬±) Ie
B.	Ib = (‚âà√≠¬¨¬± ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1) Ie
C.	Ie = (1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚Äö√†√∂‚àö¬∫) Ib
D.	Ie = (1 + ‚Äö√†√∂‚àö¬∫) Ib
Answer» E.

Discussion