1.

The complete solution of current from the information provided in the question 4.

A. i = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) + 0.7cos(500t + π/4 + 88.5⁰)
B. i = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) + 0.7cos(500t – π/4 + 88.5⁰)
C. i = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) – 0.7cos(500t – π/4 + 88.5⁰)
D. i = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) – 0.7cos(500t + π/4 + 88.5⁰)
Answer» B. i = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) + 0.7cos(500t ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚âà√¨‚àö√ë/4 + 88.5‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª)


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