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1. |
In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the particular solution. |
A. | ip = 0.6cos(500t + π/4 + 88.5⁰) |
B. | ip = 0.6cos(500t + π/4 + 89.5⁰) |
C. | ip = 0.7cos(500t + π/4 + 89.5⁰) |
D. | ip = 0.7cos(500t + π/4 + 88.5⁰) |
Answer» E. | |