1.

In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the particular solution.

A. ip = 0.6cos(500t + π/4 + 88.5⁰)
B. ip = 0.6cos(500t + π/4 + 89.5⁰)
C. ip = 0.7cos(500t + π/4 + 89.5⁰)
D. ip = 0.7cos(500t + π/4 + 88.5⁰)
Answer» E.


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