The average of n numbers $${{x}_{1}},\,{{x}_{2}},\,{{x}_{3}},\,......,\,{{x}_{n}}$$ is M. If $${{x}_{n}}$$ is replaced by $${x}'$$, then new average is [DCE 2000]

Question

The average of n numbers $${{x}_{1}},\,{{x}_{2}},\,{{x}_{3}},\,......,\,{{x}_{n}}$$ is M. If $${{x}_{n}}$$ is replaced by $${x}'$$, then new average is   [DCE 2000]

TuteeHUB · Accepted Answer

$$\frac{(n-1)M+{x}'}{n}$$

TuteeHUB · Answer

$$M-{{x}_{n}}+{x}'$$

TuteeHUB · Answer

$$\frac{nM-{{x}_{n}}+{x}'}{n}$$

TuteeHUB · Answer

$$\frac{M-{{x}_{n}}+{x}'}{n}$$

1.	The average of n numbers \[{{x}_{1}},\,{{x}_{2}},\,{{x}_{3}},\,......,\,{{x}_{n}}\] is M. If \[{{x}_{n}}\] is replaced by \[{x}'\], then new average is [DCE 2000]
A.	\[M-{{x}_{n}}+{x}'\]
B.	\[\frac{nM-{{x}_{n}}+{x}'}{n}\]
C.	\[\frac{(n-1)M+{x}'}{n}\]
D.	\[\frac{M-{{x}_{n}}+{x}'}{n}\]
Answer» C. \[\frac{(n-1)M+{x}'}{n}\]

The average of n numbers \[{{x}_{1}},\,{{x}_{2}},\,{{x}_{3}},\,......,\,{{x}_{n}}\] is M. If \[{{x}_{n}}\] is replaced by \[{x}'\], then new average is [DCE 2000]

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