The angle of dip at a place is 40.6o and the intensity of the vertical – McqOptions

MCQOPTIONS

1.	The angle of dip at a place is 40.6o and the intensity of the vertical component of the earth's magnetic field \[V=6\times {{10}^{-5}}\]Tesla. The total intensity of the earth's magnetic field (I) at this place is [MP PMT 1993]
A.	\[7\times {{10}^{-5}}tesla\]
B.	\[6\times {{10}^{-5}}tesla\]
C.	\[\frac{m}{6\pi \eta rv}\]
D.	\[9.2\times {{10}^{-5}}tesla\]
Answer» E.

Discussion

No Comment Found

Related MCQs

The variation of the intensity of magnetisation (I) with respect to the magnetising field (H) in a diamagnetic substance is described by the graph [KCET 2002]
A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be Ho and magnetic field inside the loop is H. If a magnet is suspended inside the loop, it makes angle \[\theta \] with H. Then \[\theta \]= [Orissa PMT 2004]
The angle of dip at a certain place is 30o. If the horizontal component of the earth?s magnetic field is H, the intensity of the total magnetic field is [UPSEAT 1993, 2000; MP PMT 2002]
Due to the earth's magnetic field, charged cosmic ray particles [CBSE PMT 1997]
A dip needle in a plane perpendicular to magnetic meridian will remain [NCERT 1975; MP PMT 1984; MP PET 1995]
At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively [MP PMT 1994]
A line passing through places having zero value of magnetic dip is called [CPMT 1987]
The line on the earth's surface joining the points where the field is horizontal is [MNR 1985; UPSEAT 1999; Pb PET 2004]
The angle of dip at a place is 40.6o and the intensity of the vertical component of the earth's magnetic field \[V=6\times {{10}^{-5}}\]Tesla. The total intensity of the earth's magnetic field (I) at this place is [MP PMT 1993]
The unit for molar susceptibility is