1.

Replacing the differentiation with D1, D2 in the equation 100 = 20i + 0.05 \(\frac{di}{dt} + \frac{1}{20 \times 10^{-6}} \int idt\). Find the values of D1, D2.

A. 200±j979.8
B. -200±j979.8
C. 100±j979.8
D. -100±j979.8
Answer» C. 100±j979.8


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