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1. |
Radius of a capillary is \[2\times {{10}^{-3}}m.\] A liquid of weight \[6.28\times {{10}^{-4}}N\] may remain in the capillary then the surface tension of liquid will be [RPET 2003] |
A. | \[5\times {{10}^{-3}}N/m\] |
B. | \[5\times {{10}^{-2}}N/m\] |
C. | \[\frac{{{g}_{1}}}{{{g}_{2}}}=\frac{R_{1}^{2}}{R_{2}^{2}}\] |
D. | \[50\,N/m\] |
Answer» C. \[\frac{{{g}_{1}}}{{{g}_{2}}}=\frac{R_{1}^{2}}{R_{2}^{2}}\] | |