1.

Radius of a capillary is \[2\times {{10}^{-3}}m.\] A liquid of weight \[6.28\times {{10}^{-4}}N\] may remain in the capillary then the surface tension of liquid will be     [RPET 2003]

A. \[5\times {{10}^{-3}}N/m\] 
B. \[5\times {{10}^{-2}}N/m\]
C. \[\frac{{{g}_{1}}}{{{g}_{2}}}=\frac{R_{1}^{2}}{R_{2}^{2}}\] 
D.  \[50\,N/m\]
Answer» C. \[\frac{{{g}_{1}}}{{{g}_{2}}}=\frac{R_{1}^{2}}{R_{2}^{2}}\] 


Discussion

No Comment Found