1.

Propan-1-ol can be prepared from propene by alcohol [AIIMS 2003]

A. \[{{H}_{2}}O/{{H}_{2}}S{{O}_{4}}\]
B. \[Hg{{(OAc)}_{2}}/{{H}_{2}}O\]followed by \[NaB{{H}_{4}}\]
C. \[{{B}_{2}}{{H}_{6}}\]followed by \[{{H}_{2}}{{O}_{2}}\]
D. \[C{{H}_{3}}C{{O}_{2}}H/{{H}_{2}}S{{O}_{4}}\]
Answer» D. \[C{{H}_{3}}C{{O}_{2}}H/{{H}_{2}}S{{O}_{4}}\]


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