Polar moment of inertia(IP) of a circular disc is to be determined by – McqOptions

MCQOPTIONS

1.	Polar moment of inertia(I_P) of a circular disc is to be determined by suspending it by a wire and noting the frequency of oscillations(f)
A.	I<sub>P</sub> ‚Äö√Ñ√∂‚àö‚Ä†‚àö¬™ f
B.	I<sub>P</sub> ‚Äö√Ñ√∂‚àö‚Ä†‚àö¬™ f<sup>2</sup>
C.	I<sub>P</sub> ‚Äö√Ñ√∂‚àö‚Ä†‚àö¬™ 1/f<sup>2</sup>
D.	none of the mentioned
Answer» D. none of the mentioned

Discussion

No Comment Found

Related MCQs

The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (gmoon =gearth/6) is
If the radius of gyration of a compound pendulum about an axis through c.g. is more, then its frequency of oscillation will be
The frequency of oscillation of a cylinder inside a cylinder inside a cylindrical concave surface of bigger radius compared to a small radius will be
Polar moment of inertia(IP) of a circular disc is to be determined by suspending it by a wire and noting the frequency of oscillations(f)
A body having moment of inertia of 30 kg m2 is rotating at 210 RPM and mashes with another body at rest having M.I. of 40 kg m2. The resultant speed after meshing will be
IF_THE_RADIUS_OF_GYRATION_OF_A_COMPOUND_PENDULUM_ABOUT_AN_AXIS_THROUGH_C.G._IS_MORE,_THEN_ITS_FREQUENCY_OF_OSCILLATION_WILL_BE?$
The natural frequency of a spring-mass system on earth is ‚âà√¨‚àö¬¢<sub>n</sub>. The natural frequency of this system on the moon (g<sub>moon</sub> =g<sub>earth</sub>/6) is$#
The_Bifilar_suspension_method_is_used_to_determine$
A vibratory system consists of a mass 12.5 kg, a spring of stiffness 1000N/m , and a dash-pot with damping coefficient of 15 Ns/m.The value of critical damping of the system is
A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f<sub>n</sub>), respectively, are