Point out the error, if any in the while loop.
#include
int main()
{
int i=1;
while()
{
printf("%d
", i++);
if(i10)
break;
}
return 0;
}

Question

Point out the error, if any in the while loop.
#include
int main()
{
    int i=1;
    while()
    {
        printf("%d
", i++);
        if(i>10)
           break;
    }
    return 0;
}

TuteeHUB · Accepted Answer

There should be at least a semicolon in the while

TuteeHUB · Answer

There should be a condition in the while loop

TuteeHUB · Answer

The while loop should be replaced with for loop.

TuteeHUB · Answer

No error

1.	Point out the error, if any in the while loop. #include int main() { int i=1; while() { printf("%d\n", i++); if(i>10) break; } return 0; }
A.	There should be a condition in the while loop
B.	There should be at least a semicolon in the while
C.	The while loop should be replaced with for loop.
D.	No error
Answer» B. There should be at least a semicolon in the while

Point out the error, if any in the while loop. #include int main() { int i=1; while() { printf("%d\n", i++); if(i>10) break; } return 0; }

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