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1. |
On which of the following lines lies the point of intersection of the line, \(\frac{{x - 4}}{2} = \frac{{y - 5}}{2} = \frac{{z - 3}}{1}\) and the plane, x + y + z = 2 |
A. | \(\frac{{x + 3}}{3} = \frac{{4 - y}}{3} = \frac{{z + 1}}{{ - 2}}\) |
B. | \(\frac{{x - 4}}{1} = \frac{{y - 5}}{1} = \frac{{z - 5}}{{ - 1}}\) |
C. | \(\frac{{x - 1}}{1} = \frac{{y - 3}}{2} = \frac{{z + 4}}{{ - 5}}\) |
D. | \(\frac{{x - 2}}{2} = \frac{{y - 3}}{2} = \frac{{z + 3}}{3}\) |
Answer» D. \(\frac{{x - 2}}{2} = \frac{{y - 3}}{2} = \frac{{z + 3}}{3}\) | |