If the plane 2x - y + 2z + 3 = 0 has the distances \(\frac{1}{3}{\rm{\;and\;}}\frac{2}{3}\) units from the planes 4x - 2y + 4z + λ = 0 and 2x - y + 2z + μ = 0, respectively, then the maximum value of λ + μ is equal to:

If the plane 2x - y + 2z + 3 = 0 has the distances \(\frac{1}{3}{\rm{\

1.	If the plane 2x - y + 2z + 3 = 0 has the distances \(\frac{1}{3}{\rm{\;and\;}}\frac{2}{3}\) units from the planes 4x - 2y + 4z + λ = 0 and 2x - y + 2z + μ = 0, respectively, then the maximum value of λ + μ is equal to:
A.	9
B.	15
C.	5
D.	13
Answer» E.

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If the plane 2x - y + 2z + 3 = 0 has the distances \(\frac{1}{3}{\rm{\;and\;}}\frac{2}{3}\) units from the planes 4x - 2y + 4z + λ = 0 and 2x - y + 2z + μ = 0, respectively, then the maximum value of λ + μ is equal to:

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