nth derivative of y = sin2x cos3x is

1.	nth derivative of y = sin²x cos³x is
A.	<sup>1</sup> <sub>8</sub> cos u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 5<sup>n</sup> cos u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 3<sup>n</sup> cos u2061(3x + <sup>n </sup> <sub>2</sub>)
B.	<sup>1</sup> <sub>8</sub> sin u2061(x+<sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 5<sup>n</sup> cos u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 3<sup>n</sup> cos u2061(3x + <sup>n </sup> <sub>2</sub>)
C.	<sup>1</sup> <sub>8</sub> cos u2061(x+<sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 5<sup>n</sup> sin u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 3<sup>n</sup> sin u2061(3x + <sup>n </sup> <sub>2</sub>)
D.	<sup>1</sup> <sub>8</sub> sin u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 5<sup>n</sup> sin u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 3<sup>n</sup> sin u2061(3x + <sup>n </sup> <sub>2</sub>)
Answer» B. <sup>1</sup> <sub>8</sub> sin u2061(x+<sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 5<sup>n</sup> cos u2061(x + <sup>n </sup> <sub>2</sub>) <sup>1</sup> <sub>16</sub> 3<sup>n</sup> cos u2061(3x + <sup>n </sup> <sub>2</sub>)

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