If nth derivative of eax sin (bx+c) cos (bx+c) is, eax rn sin (bx+c+n 2) cos (bx+c+n 2) then,

r = ( sqrt{a^2+8b^2}, alpha=tan^{-1} u2061 frac{4b}{a} )

r = ( sqrt{a^2+b^2}, alpha=tan^{-1} frac{ u2061b}{a} )

r = ( sqrt{a^2+4b^2}, alpha=tan^{-1} u2061 frac{2b}{a} )

r = ( sqrt{a^2+8b^2}, alpha=tan^{-1} u2061 frac{4b}{a} )

r = ( sqrt{a^2+16b^2}, alpha=tan^{-1} frac{ u20614b}{a} )

If nth derivative of eax sin (bx+c) cos (bx+c) is, eax rn sin (bx+c+n

1.	If nth derivative of e^ax sin (bx+c) cos (bx+c) is, e^ax rⁿ sin (bx+c+ⁿ ₂) cos (bx+c+ⁿ ₂) then,
A.	r = ( sqrt{a^2+b^2}, alpha=tan^{-1} frac{ u2061b}{a} )
B.	r = ( sqrt{a^2+4b^2}, alpha=tan^{-1} u2061 frac{2b}{a} )
C.	r = ( sqrt{a^2+8b^2}, alpha=tan^{-1} u2061 frac{4b}{a} )
D.	r = ( sqrt{a^2+16b^2}, alpha=tan^{-1} frac{ u20614b}{a} )
Answer» C. r = ( sqrt{a^2+8b^2}, alpha=tan^{-1} u2061 frac{4b}{a} )