\(\mathop \smallint \limits_0^{\frac{\pi }{2}} {e^{\sin x}}\cos x\;dx\) is equal to

\(\mathop \smallint \limits_0^{\frac{\pi }{2}} {e^{\sin x}}\cos x\;dx\

1.	\(\mathop \smallint \limits_0^{\frac{\pi }{2}} {e^{\sin x}}\cos x\;dx\) is equal to
A.	e + 1
B.	e - 1
C.	e + 2
D.	e
Answer» C. e + 2

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\(\mathop \smallint \limits_0^{\frac{\pi }{2}} {e^{\sin x}}\cos x\;dx\) is equal to

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